Answer :
Ferric Sulphate
Fe2(SO4)3=Fe2S3O12
Oxidation no. of iron is 3 & oxygen is -2
So, Fe charge =2*3=6
O charge=12*-2=-24
Fe+O=6-24=-18
To make charge 0,
-18+S3=0
=> S3=18 S=6
Ferrous Sulphte,
FeSO4
Oxidation no. og Fe is 2 and of O is -2
So, Fe charge=2
O charge=4*-2=-8
F+O=2-8=-6
As in ferric sulphate
-6+S=0
S=6
Ferric Sulphate : Iron (III) sulphate valency of iron is 3.
Chemical formula: Fe₂ (SO₄)₃ Ions: Fe³⁺ and SO₄²⁻
oxidation number of Fe is +3
oxidation number of SO₄ is -2
Oxidation number of oxygen (in general) is - 2
hence, - 2 = S + 4 * -2 => S = 6
oxidation number of Sulphur in Ferric Sulphate 6
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Ferrous sulphate or Iron (II) suplhate : chemical formula: Fe SO₄
Here Iron has valency - oxidation number 2. as the ions are: Fe²⁺ SO₄²⁻
Hence the oxidation number of Sulphur will be 6 like in the case of Ferric sulphate. It will be 6.
Chemical formula: Fe₂ (SO₄)₃ Ions: Fe³⁺ and SO₄²⁻
oxidation number of Fe is +3
oxidation number of SO₄ is -2
Oxidation number of oxygen (in general) is - 2
hence, - 2 = S + 4 * -2 => S = 6
oxidation number of Sulphur in Ferric Sulphate 6
===================
Ferrous sulphate or Iron (II) suplhate : chemical formula: Fe SO₄
Here Iron has valency - oxidation number 2. as the ions are: Fe²⁺ SO₄²⁻
Hence the oxidation number of Sulphur will be 6 like in the case of Ferric sulphate. It will be 6.