Answer :

Step-by-step explanation:

To find the quadratic polynomial with those zeros, we can use the fact that the zeros of a quadratic polynomial can be expressed as (x - r)(x - s), where r and s are the zeros.

In this case, the zeros are -√2/3 and √3/4.

So, the quadratic polynomial can be written as:

(x - (-√2/3))(x - (√3/4))

Simplifying this expression, we get:

(x + √2/3)(x - √3/4)

To get rid of the square roots in the denominator, we can multiply the numerator and denominator of each term by the conjugate of the denominator:

(x + √2/3)(x - √3/4) * (4/4)

Expanding this expression, we have:

(4x + 4√2/3)(4x - 3√3/4)

Multiplying these terms further, we get:

16x^2 - 12√3x + 16√2x - 3√6

So, the quadratic polynomial with zeros -√2/3 and √3/4 is:

16x^2 + (4√2 - 12√3)x - 3√6

I hope that helps! Let me know if you have any more questions.

hi Shivani..!

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