## Answer :

**Step-by-step explanation:**

__To find the quadratic polynomial with those zeros, we can use the fact that the zeros of a quadratic polynomial can be expressed as (x - r)(x - s), where r and s are the zeros.__

__In this case, the zeros are -√2/3 and √3/4.__

__So, the quadratic polynomial can be written as:__

__(x - (-√2/3))(x - (√3/4))__

__Simplifying this expression, we get:__

__(x + √2/3)(x - √3/4)__

__To get rid of the square roots in the denominator, we can multiply the numerator and denominator of each term by the conjugate of the denominator:__

__(x + √2/3)(x - √3/4) * (4/4)__

__Expanding this expression, we have:__

__(4x + 4√2/3)(4x - 3√3/4)__

__Multiplying these terms further, we get:__

__16x^2 - 12√3x + 16√2x - 3√6__

__So, the quadratic polynomial with zeros -√2/3 and √3/4 is:__

__16x^2 + (4√2 - 12√3)x - 3√6__

__I hope that helps! Let me know if you have any more questions.__

__h____i____ ____Shivani____.____.____!__