Answer :


Let the number be x

ATQ-x/3-x/4=15  (LCM IS 12)

4x-3x/12=15

x/12=15 

x=15*12  (transporting x from LHS to RHS)

x=180


let that number is x
a/q,
         [tex] \frac{x}{3} = \frac{x}{4} +15[/tex]
[tex]or, \frac{x}{3} - \frac{x}{4} =15[/tex]
[tex]or, \frac{4x-3x}{12} = 15[/tex]
[tex]or, x = 180[/tex]
therfore number = 180

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